The velocity time graph of a ball of mass `20g` moving along a straight line on a long table is given in (figure) How much force does the table exert on the ball to bring it to rest?

Explanation

Here, `m=20g = 20xx10^(-3)kg, F=?`
From the graph, (figure)
initial speed, `u=20 cm//s = 0.2 m//s`, final speed, `v=0`
time taken, `t=10s`
As, `F=ma = (m(v-u))/t= (20xx10^(-3)(0-0.2))/10= -4xx10^(4)N`