A `150g` ball travelling at `30m//s` strikes the plam of a player's hand and is stopped in `0.06 sec`. Calculate the force exerted by the ball on the hand.

Explanation

Here, `m=150g = 150xx10^(-3)kg, u=30m//s, v=0, t=0.06s, F=?`
From `F=ma=(m(v-u))/t=(150xx10^(-3)(0-30))/(0.06)= -75N`
Negative sign is for stopping force.