A bullet of mass `20 gram` moving with a velocity of `300m//s` gets embedded in a freely suspened wooden block of mass `880 gram`. What is the velocity acquired by the blocks?

Explanation

To solve the problem, we will use the principle of conservation of momentum. According to this principle, the total momentum before an event must equal the total momentum after the event, provided no external forces act on the system.

### Step-by-Step Solution:

1. **Identify the masses and velocities:**
- Mass of the bullet (m1) = 20 grams = 20 × 10^(-3) kg (since 1 gram = 10^(-3) kg)
- Velocity of the bullet (v1) = 300 m/s
- Mass of the wooden block (m2) = 880 grams = 880 × 10^(-3) kg
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