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(a)What wii be the percentage change in ...

(a)What wii be the percentage change in momentum of a body when both its mass and velocity are doubled?
(b)A force of `200N` is required just to move a table floor at a constant speed. What is the frictional force exerted by the floor on the table?

Text Solution

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(a)`p= mv , p' = (2m) (2v)= 4mv`
% age increase in momentum `=((p'-p))/pxx100= ((4m v-mv))/(mv)xx100= 300%`
(b)Frictional force = applied force `200N`
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