A man weighing `60kg` runs along the rails with a velocity of `18km//h` and jumps into a car of mass 10 quintal standing on the rails. Calculate the velocity with which the car will start travelling on the rails .

Explanation

Here, `m_(1)=60kg, v_(1)= 18km//h= (18xx1000m)/(60xx60s)=5m//s`
`m_(2)= 10 "quintal" = 1000kg, v_(2)=0, v=?`
According to the prunciple of conservation of linear momentum,
`(m_(1)+m_(2))v=m_(1)v_(1)+m_(2)v_(2)=m_(1)v_(1)`
`:. v=(m_(1)v_(1))/((m_(1)+m_(2)))= (60xx5)/(60+1000)= (300)/(1060)= 0.28m//s`.