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A body of mass 2kg moving with a velocit...

A body of mass `2kg` moving with a velocity of `10m//s` is brought to rest in `5 sec`. Calculate the stopping force applied.

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`F=m a = (m(v-u))/t=(2(0-10))/5= -4N`
Negative sign indicates opposite direction of force.
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PRADEEP-FORCES AND LAWS OF MOTION-ASSESSSMENT THROUGH PAPER-PEN TEST
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