A person manages to push a car of mass `800 kg` with a uniform velocity along a level road. When another person joins him and pushes the car with an equal force, the acceleration produced is `0.5m//s^(2)`. Calculate the force with which each person pushes the car.

Explanation

Let `F` be the force applied by each person. In the first case, when velocity is uniform, F=f=force of friction. In the second case, applied force `= F+F= 2F`
Net force producing acceleration `= 2F-f = 2F-F= m a = 800xx0.5= 400N`