A geostationary satellite is orbiting the earth at a height 5 R above the surface of earth, where R is radius of earth. Find the time period of another of another satellite at a height of 2 R from the surface of earth.

Explanation

Here, `r_(1)=5R+R=6R`, or `T_1=24` hour (for geostationary satellite)
`r_(2)=2R+R=3R`, or `T_(2)=?`
According to Keplar's third law,
`(T_(2)^(2))/(T_(1)^(2))=(r_(2)^(3))/(r_(1)^(3))=((3R)/(6R))^(3)=(1)/(8)`
`T_(2)=(T_(1))/(sqrt(8))=(24)/(2sqrt(2))h=6sqrt(2)h`.