A stone is thrown verticaly upward with an initial velocity of `40m//s`. Taking `g=10m//s^(2)`, find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?

Explanation

To solve the problem step by step, we can break it down into three main parts: calculating the maximum height, determining the net displacement, and finding the total distance covered by the stone.

### Step 1: Calculate the Maximum Height

We can use the following kinematic equation to find the maximum height (S) reached by the stone:

\[
v^2 = u^2 + 2aS
...