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A stone is thrown verticaly upward with ...

A stone is thrown verticaly upward with an initial velocity of `40m//s`. Taking `g=10m//s^(2)`, find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?

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To solve the problem step by step, we can break it down into three main parts: calculating the maximum height, determining the net displacement, and finding the total distance covered by the stone. ### Step 1: Calculate the Maximum Height We can use the following kinematic equation to find the maximum height (S) reached by the stone: \[ v^2 = u^2 + 2aS ...
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  • Question Stimulus A stone is thrown vertically upwards with an initial velocity of 30 ms^(-1) . Acceleration due to gravity g = 10 ms^(-2) . The maximum height reached by the stone is

    A
    30 m
    B
    4.5 m
    C
    45 m
    D
    90 m

  • A stone of 3kg is thrown vertically upward with an initial speed of 20m/s. If g=10 m//s^(2) , then find the kinetic energy and potential energy after 1s.

    A
    600, 1800
    B
    600,0
    C
    100, 500
    D
    150, 450

  • A stone of 3 kg is thrown vertically upward with an initial speed of 20 m/s. If g = 10 m//s^2 , then find the kinetic energy and potential energy after 1 s.

    A
    600, 1800
    B
    600,0
    C
    100, 500
    D
    150, 450

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