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If distance between two masses is quadru...

If distance between two masses is quadrupled, what will be the new force of attraction between them? given the initial gravitational pull is 9.8N.

Text Solution

Verified by Experts

As `Fprop(1)/d^(2)`
`:. F_(2)/F_(1)=(d_(1)/d_(2))^(2)=((1)/(4))^(2)`
`F_(2)=F_(1)/(16)=(9.8)/(16)=0.61N`
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