Home
Class 9
PHYSICS
The value of acceleration due to gravity...

The value of acceleration due to gravity

A

is same on equator and poles

B

is least on poles

C

is least on equator

D

increase from pole to equator

Text Solution

Verified by Experts

The correct Answer is:
C

The value of acceleration due to gravity is least on equater, as equatorial radius is maximum.
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    PRADEEP|Exercise Mock Test (3)|25 Videos
  • GRAVITATION

    PRADEEP|Exercise Model Test paper (1)|36 Videos
  • GRAVITATION

    PRADEEP|Exercise Paper-pen test|29 Videos
  • FORCES AND LAWS OF MOTION

    PRADEEP|Exercise MOCK TEST|36 Videos
  • MOTION

    PRADEEP|Exercise Mock test|24 Videos

Similar Questions

Explore conceptually related problems

By considering earth to be non spherical. STATEMENT -1 : As one moves from equator to the pole of earth, the value of acceleration due to gravity increases. and STATEMENT -2 : If earth stops rotating about its own axis, the value of acceleration due to gravity will be same at pole and at equator.

The ratio between the values of acceleration due to gravity at a height 1 //km above and at a depth of 1 km below the Earth’s surface is (radius of Earth is R)

A small steel ball of mass m and radius r is falling under gravity through a viscous liquid of coefficient of viscosity eta . If g is the value of acceleration due to gravity. Then the terminal velocity of the ball is proportional to (ignore buoyancy)

As we go from pole to the equator, the effective value of acceleration due to gravity decreases due to

What is depth at which value of acceleration due to gravity becomes 1/n times value that at surface of earth

The depth at which the effective value of acceleration due to gravity is g/4 is (R=radius of the earth)

Choose the correct alternative :The effect of rotation on the effective value of acceleration due to gravity is greatest at the equator/poles.

Assertion : The time period of a freely falling pendulum is infinite. Reason : The effective value of acceleration due to gravity becomes zero.

Acceleration due to gravity at earth's surface if 'g' m//s^(2) . Find the effective value of acceleration due to gravity at a height of 32 km from sea level : (R_(e)=6400 km)

Assertion (A): At pole value of acceleration due to gravity (g) is greater than that of equator. Reason (R) : Earth rotates on its axis in addition to revolving round the sun.