If mass of earth is roughly 80 times the mass of moon and diameter of earth is roughly 3.6 times the diameter of moon, show that weight of an object on moon will be roughly `(1)/(6)`th of the weight of the object on earth.

Explanation

`W_(m)/W_(e)=(GM_m//R_(m)^(2))/(Gm_(e)//R_(e)^(2))=M_(m)/M_(e)(R_(e)/R_(m))^(2)=(1)/(80)(3.6)^(2)=0.162`
`W_(m)0.162 W_(e)=(1)/(6)W_(e)`