A 10 gram bullet is shot from a 2 kg gun with a velocity of 400 `m//s`. What is the speed of recoil of the gun ?

Explanation

Here, `m_(1)=10 g=10^(-2) kg, m_(2)=2kg , v_(1)=400 m//s,v_(2) = ?`
`v_(2)=-(m_(1)v_(1))/(m_(2))=-(10^(-2)xx400)/(2)=- 2 m//s`.