a car weight 1200 kg. This weight is evenly distributed on 4 wheels. If the pressure in each tyre is `15kg((wf)/(cm^2))`. What is the area of each tyre in contact.

Explanation

Thrust on each tyre, `F=(1200)/(4)=300kgwt`,`P=15kg((wt)/(cm^2))`
As `P=(F)/(A)`,`A=(F)/(P)=(300kgwt)/(15kg((wt)/(cm^2)))=20cm^2`