A rectangular block of wood is floating on the surface of a container filled with water. You observe that `80%` of the block is under wate whereas rest is above the surface. Find the density of wood.

Explanation

As `F_B=rho_(water)h'Ag=rho_(wood)Hag`
`rho_("wood")=rho_("water")((h')/(h))=(1000(kg)/(m^3))((80)/(100))=800(kg)/(m^3)`.