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An engine pulls a train 1 km over a leve...

An engine pulls a train 1 km over a level track. Calculate the work done by the train given that the frictional resistance is `5xx10^5 N.`

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Here, frictional resistance, `F = 5xx10^5N`
distance through which the train moves, `s =1 km = 1000 m`
Work done by the frictional force, i.e., `W = -Fs = - (5xx10^5 N) (1000 m) = - 5xx10^8J`
(F and s are in opposite directions)
Obviously, work done by the train is `5xx10^8J`
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