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A 5 kg ball is thrown upwards with a spe...

A 5 kg ball is thrown upwards with a speed of `10 m//s`. (a) Find the potential energy when it reaches the highest point. (b) Calculate the maximum height attained by it.

Text Solution

Verified by Experts

Here,mass of the ball, `m = 5 kg`,
speed of the ball, `upsilon = 10 m//s`
Kinetic energy of the ball, `E_k = (1)/(2) mv^(2) =(1)/(2) (5kg)(10m//s)^2 =250 J`
When the ball reaches the highest point its kinetic energy becomes zero as the entite kinetic energy
convrted into its potential energy `(E_p)i.e.,`
`E_p = 250 J`
If h is the maxmum height attained by the ball,
`E_p =mgh`
From eqns. (i) and (ii), `mgh =250 J` or `h = (250 J)/(mg) =(250J)/((5kg)(10m//s^(2))) = 5m`
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