Calculate the work required to be done to stop a car of `1500 kg` moving with a speed of `60 km//h`.

Explanation

Here, mass of the car, m = 1500 kg
initial velocity of the car `u = 60 km//h = (60xx1000m)/(60 xx60s) = (50)/(3) m //s`
Initial kinetic energy of the car, `E_(ki) = (1)/(2)m u^2`
`=(1)/(2) (1500kg) ((50)/(3)m//s)^2 = 208333.3J`
Final kinetic energy of the car, `E_(kf) = (1)/(2)m upsilon^2 = 0 (upsilon = 0)`
Change kinetic energy of the car ` = E_(ki) - E_(kf) = 208333.3 J`
Work done to stop the car = change in kinetic energy of the car = 208333.3 J