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300 Jof work is done in slide a 2kg bloc...

`300 J`of work is done in slide a `2kg` block up an inclined plane of height `10m`. `Taking g = 10 m//s^(2), work done against friction is

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Verified by Experts

Work done against friction = total work done - PE at a height of 10m
= `(300 J) - (20 xx 10 xx10) J =100 J`
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