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A truck weighing 5000 kg f and a cart we...

A truck weighing 5000 kg f and a cart weighing 500 kg f are moving with the same speed. Compare their kinetic energies.

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The correct Answer is:
A
`(KE of truck)/(KE of cart) = ((1)/(2)m_1 upsilon^2)/((1)/(2)m_2upsilon^2) = (m_1)/(m_2) = (5000kg f)/(500kg f) =10 =10:1`
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