`(7)/(10)+(2)/(5)+(3)/(2)=`

The arrangement of rational numbers (-7)/(10),(5)/(-8),(2)/(-3) in ascending order is (2)/(-3),(5)/(-8),(-7)/(10) (b) (5)/(-8),(-7)/(10),(2)/(-3) (c) (-7)/(10),(5)/(-8),(2)/(-3)(d)(-7)/(10),(2)/(-3),(5)/(-8)

Verify the following: (i) ((3)/(4)+(-2)/(5))+(-7)/(10)=(3)/(4)+((-2)/(5)+(-7)/(10)) (ii) ((-7)/(11)+(2)/(-5))+(-13)/(22)=(-7)/(11)+((2)/(-5)+(-13)/(22)) (iii) -1+((-2)/(3)+(-3)/(4))=(-1+(-2)/(3))+(-3)/(4)

[[1,0,-13,4,50,-6,-7]]=[[(1)/(10),(3)/(10),(1)/(5)(21)/(20),-(7)/(20),-(2)/(5)-(9)/(10),(3)/(10),(1)/(5)]]

(7)/(2)+(6)/(10)+(5)/(3)=

5(1)/(7)-{3(3)/(10)-:(2(4)/(5)-(7)/(10))}

(3)/(10)+(7)/(10^(2))+(3)/(10^(3))+(7)/(10^(4))+(3)/(10^(5))+(7)/(10^(6))+

Simplify : ((1)/(12) + ((-3)/( 4)) + (7)/(8)) xx (3 (2)/(5) - (7)/(10) + ((-2)/( 15)) - 10 (1)/(30))

Calculate each of the following using multiplication. (i) (3)/(7) of (2)/(5) (ii) (3)/(5) of (2)/(7) (iii) (2)/(3) of (3)/(4) iv) (5)/(6) of (3)/(10) .

Simplify: 5/4-7/6-(-2)/3 (ii) (-2)/5-(-3)/(10)-(-4)/7

Simplify: 5/4-7/6-(-2)/3 (ii) (-2)/5-(-3)/(10)-(-4)/7