A periodic longitudinal wave is send on a slinky. The wave proceeds at a speed of `48 m//s` and each particle oscillates at a frequency of `12 Hz`. Calculate the minimum separation between the positions where the slinky is most compressed.

Answer

2 cm

Explanation

Here, `v = 48 cm//s, v = 12 Hz, lamda = (v)/(v) = (48 cm//s)/(12//s) = 4 cm`.