Radio Ceylon broadcasts at `25 m`. What is the frequency of the station ?

Answer

`1.2 xx 10^7 Hz`

Explanation

Here, `lamda = 25 ,` speed of radio waves, `v = 3 xx 10^8 m//s` (speed of light in vacuum)
Thus, `v = (v)/(lamda) = (3 xx 10^8)/(25) = 1.2 xx 10^7 Hz`.