The speed of sound in air on a summer day is `350 m//s`. What is the air temperature ?

Explanation

Speed of sound in air at `0^@ C = 331 m//s`
Speed of sound in air at `t^@ C = 350 m//s`
Change in speed of sound with `t^@ C` change in temperature `= 350 m//s - 331 m//s = 19 m//s`.
Since speed of sound increases by `0.6 m//s` for `1^@ C` increse in temperature,
temperature `(t^@ C)` of air `= ((19 m//s)/(0.60 m//s)) .^@C = 31.7^@ C`.
This is an approximate method of relating speed of sound with temperature. The exact relation between speed of sound (v) and T (temperature in degrees kelvin) is `v prop sqrt(T)` You will learn this in Class (XI).