A body of mass `10 g` floats with `(3//4)th` of its volume above water. Find its relative density and volume.

Explanation

If `V` is the volume of the body, then volume of water displaced `= V//4`
Since for the body to floats, mass of water displaced is equal to the mass of the body, i.e., `10 g`,
`(V//4)rho_w = 10 g`
or `V = 40 cm^3` `(as rho_w = 1 g//cm^3)`
Density of body, `rho = (10 g)/(40 cm^3) = 0.25 g//cm^3`
Relative density of body `= (rho)/(rho_w) = (0.25 g//cm^3)/(1 g//cm^3) = 0.25`.