An object 3 cm high is held at a distance of 50 cm from a diverging mirror of focal length 25 cm. Find the nature, position and size of the image formed.

Explanation

Here, `h_(1)= 3cm, u = -50cm,f=25cm`.
From `(1)/(v) + 1/u = (1)/(f)`
`(1)/(v) = (1)/(f) - 1/u=1/25 - 1/-50 = 3/50`
`v= 50/3 =16*67 cm`.
As v is positive, image is behind the mirror. It is virtual and erect.
From `m=(h_(2))/(h_(1))= -v/u`
`(h_(2))/(3) = (-50//3)/(-50)=(1)/(3) " " h_(2)=1cm`