(a) For a normal eye, what is the least distance of distinct vision ?
(b) What is the maximum power of accomodation of a normal eye ?

Explanation

For a person having normal vision, least distance of distinct vesion is `d = 25 cm`.
Therefore, maximum power of accommodation,
`P = (100)/(f) = (100)/(d) = (100)/(25) = 4 diopre`.