What is the condition for minimum deviat...

What is the condition for minimum deviation through then prism ? What is prism formula ?

Text Solution

Verified by Experts

The condition for minimum deviation through a prism is that angle of incidence (i) is equal to angle of emergence ( e).In that case, the refracted ray `EF` becomes parallel to the base `bC` of the prism.
If `D_m` is the angle of minimum deviation, then the prism formula is
`mu =(sin(A + D_m)//2)/(sin A//2)`
Here, `mu`is refraction index of the material of the prism.

Topper's Solved these Questions

THE HUMAN EYE AND COLOURFUL WORLD
PRADEEP|Exercise Higher Order Thinking|6 Videos
THE HUMAN EYE AND COLOURFUL WORLD
PRADEEP|Exercise Value Based Question|4 Videos
THE HUMAN EYE AND COLOURFUL WORLD
PRADEEP|Exercise (Additional)Long answer|10 Videos
SOURCES OF ENERGY
PRADEEP|Exercise Mock Test|20 Videos

The angle of incidence for a ray of light at a refracting surface of a prism is 45^@ . The angle of prism is 60^@ . If the ray suffers minimum deviation through the prism, then the angle of minimum deviation is:

`30^@`

`60^@`

`45^@`

`90^@`

The angel of incidence for a fay of light at a refracting sufrace of a prism is 45^(@). The angle of prism is 60^(@) If the ray suffers minimum deviation through the prism, the angle of minimum deviation and refractive index of the material of the prism repectively, are

`30^(@),sqrt2`

`45^(@),sqrt2`

`30^(@),1/sqrt2`

`45^(@),1/sqrt2`

The angle of incidence for a ray of light at a refracting surface of a prism is 45^(@) . The angle of prism is 60^(@) . If the ray suffers minimum deviation through the prism. The angle of minimum deviation and refractive index of the material of the prism respectively, are

`45^(@), sqrt(2)`

`30^(@), (1)/(sqrt(2))`

`45^(@),(1)/(sqrt(2))`

`30^(@), sqrt(2)`