Home
Class 10
PHYSICS
Saniya and Shikha are friends studying t...

Saniya and Shikha are friends studying together in grade `IV`. While Saniya can read a book keeping it at normal distance of about `25 cm`, Shikha has to keep the book at about `50 cm` from her eyes. Shikha feels it is a natural defect of her eyes, which cannot be corrected. Saniya is smarter. She tells her that medical science is advanced and there must be treatment for this problem. The doctor, on checking, prescribes spectacles of suitable power to Shikha and her vision with glasses becomes normal.
What the above passage and answer the following quentions :
(i) What defect was there in the vision of Shikha ?
(ii) What could be the causes of this defect ?
(iii) Calculate nature and power of the lens prescribed by the doctor. Assume that Shikha can read the book from a distance of `25 cm`, which she could do from a distance of `50 cm` without glasses.
(iv) What are the values of life displayed by Saniya ?]

Text Solution

Verified by Experts

(i) Shikha is suffering from Hypermetropia or long sightedness.
(ii) Two possible causes of this defect are :
decrease in size of eye ball , increase in focal length of eye lens.
(iii) Here, `u = -25 cm, v = -50 cm`
`(1)/(f)=(1)/(v)-(1)/(u)=(1)/(-50)+(1)/(25)=(1)/(50), f = 50 cm`
`P = (100)/(f) = (100)/(50) = + 2 D`
The lens must be convex.
(iv) Saniya has displayed concern for the health of Shikha whi is her friend. Her awareness has helped Shikha to get her problem treated. But for Saniya, Shikha has resigned herself to live with the problem. Saniya provided that a friend in need is a friend indeed.
Promotional Banner

Topper's Solved these Questions

  • THE HUMAN EYE AND COLOURFUL WORLD

    PRADEEP|Exercise Problem For Practice|8 Videos
  • THE HUMAN EYE AND COLOURFUL WORLD

    PRADEEP|Exercise (Exemplar)Multiple Choice|14 Videos
  • THE HUMAN EYE AND COLOURFUL WORLD

    PRADEEP|Exercise Higher Order Thinking|6 Videos
  • SOURCES OF ENERGY

    PRADEEP|Exercise Mock Test|20 Videos

Similar Questions

Explore conceptually related problems

The near point of a hypermetropic eye is 1 m. What is the nature and power of the lens required to correct this defect ? (Assume that the near point of the normal eye is 25 cm).

A far sighted person has a near point of 60"cm" . What power lens should be used for eye glasses such that the person can be read this book at a distance of 25 cm.

A far sighted person has a near point of 60 cm. What power lens should be used for eye glasses such that the person can read a book at a distance of 25 cm.

The near point of a defective eye is 25 cm from the eye. Calculate focal length of the lens required by her to read a book placed at 20 cm .

The near point of a hypermetropic eye is 50 cm . Calculate the power of the lens to enable him to read a book at 40 cm ?

A man, wearing glasses of power +2D can read clearly a book placed at a distance of 40cm from the eye. The power of the lens required so that he can read at 25cm from the eye is

A person has a minimum distance of distinct vision as 50cm. The power of lenses required to read a book at a distance of 25cm is