Three resistors of `6 Omega, 3 Omega and 2 Omega` are connected together so that the total resistance is greater than `6 Omega` but less than `8 Omega`. Draw a diagram to show this arrangement and calculate its total resistance.

Explanation

To solve the problem of finding the total resistance of three resistors (6 Ω, 3 Ω, and 2 Ω) connected in such a way that the total resistance is greater than 6 Ω but less than 8 Ω, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Arrangement**:
We need to connect the resistors in a way that the total resistance is greater than 6 Ω but less than 8 Ω. A good approach is to connect the 6 Ω resistor in series with the combination of the other two resistors (3 Ω and 2 Ω) in parallel.

2. **Calculate the Equivalent Resistance of the Parallel Resistors**:
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