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Evaluate int(40^(@))^(60^(@)) (d theta)/...

Evaluate `int_(40^(@))^(60^(@)) (d theta)/(( theta - theta_0)) , where` `theta_0 = 20^@`

A

`0.931`

B

`0.6931`

C

`0.61`

D

`0.9`

Text Solution

Verified by Experts

The correct Answer is:
B
`int_(40^@)^(60^@) (d theta)/((theta - theta_0)) = [lotg_e (theta - theta_0)]_(40)^(60) = log_e (60 -20) - log_e(40 - 20)`
`=log_e (40)/(20) = log_e 2 = 2.3026 log_(10) 2 = 2.3026 xx0.3010 = 0.6931`
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