Home
Class 11
PHYSICS
The value of acceleration due to gravity...

The value of acceleration due to gravity `(g)` at height `h` above the surface of earth is given by
`g^'=(gR^2)/((R+h)^2)`. If `hlt ltR`, then prove that `g^'=g(1-(2h)/(R))`.

Text Solution

Verified by Experts

The correct Answer is:
`g(1 - 2 h//R)`
Promotional Banner

Topper's Solved these Questions

  • MATHEMATICAL TOOLS

    PRADEEP|Exercise M.C.Q|5 Videos

  • MATHEMATICAL TOOLS

    PRADEEP|Exercise Fill in the blanks|5 Videos

  • MATHEMATICAL TOOLS

    PRADEEP|Exercise Fill in the blanks|5 Videos

  • LAWS OF MOTION

    PRADEEP|Exercise Assertion- Reason Type Questions|17 Videos

  • OSCILLATIONS AND WAVES

    PRADEEP|Exercise multiple choice Questions|13 Videos

Similar Questions

Explore conceptually related problems

The value of acceleration due to gravity (g) at height h above the surface of earth is given as g^()=(gR)^(2)/((R+h))^(2) If h lt lt R , then prove that g^()=g(1-(2h)/(R))

Find ratio of acceleration due to gravity g at depth d and at height h where d=2h

Let g be the acceleration due to gravity on the earth's surface.

The acceleration due to gravity at a height h above the surface of the earth has the same value as that at depth d= ____below the earth surface.

If R is the radius of the earth, then the value of acceleration due to gravity at a height h from the surface of the earth will become half its value on the surface of the earth if

The value of the acceleration due to gravity is g1 at a height h=(R)/(2)(R= radius of the earth) from the surface of the earth.It is again equal to (g1/2) at a depth d below the surface of the earth.The ratio d/R equals:

What is the acceleration due to gravity at a height h ( = radius of the earth) from the surface of the earth ? ltbgt (g=9.8m//s^(2))

The value of the acceleration due to gravity is g_(1) at a height h=(R)/(2) (R=radius of the earth) from the surface of the earth.It is equal to 2g_(1) at a depth d below the surface of the earth.The ratio ((d)/(R)) is equal to:

Given, acceleration due to gravity on surface of earth is g. if g' is acceleration due to gravity at a height h above the surface of earth, then

Given g_(d) = g(1-(d)/(R)) where gd and g are the accelerations due to gravity at a depth 'd' km, and on the surface of the Earth, respectively, R is the radius of the Earth, then the depth at which g_(d) = (g)/(2) is______.

PRADEEP-MATHEMATICAL TOOLS-PROBLEMS FOR PRACTICE
  1. Evaluate (999)^(1//3) upto 4 places of decimal.

    Text Solution

    |

  2. Evaluate sqrt(26) correct upto four places of decimal.

    Text Solution

    |

  3. The value of acceleration due to gravity (g) at height h above the sur...

    Text Solution

    |

  4. Simplify the following. Using Binomial theoremE=K[(1+(Deltatheta)/thet...

    Text Solution

    |

  5. Evaluate (1.056)^(1//3) correct up to the four places of decimal.

    Text Solution

    |

  6. Identify , whether the following equation represent a straight line , ...

    Text Solution

    |

  7. Identify , whether the following equation represent a straight line , ...

    Text Solution

    |

  8. Identify , whether the following equation represent a straight line , ...

    Text Solution

    |

  9. Find the value of the following : (a) sin ( - 30^(@)) (b) cos (-60^(@...

    Text Solution

    |

  10. Find the value of the following : (a) sin 120^(@) (b) cos 135^(@) (c ...

    Text Solution

    |

  11. Find the value of the following : (a) sin 210^(@) (b) cos 220^(@) (c ...

    Text Solution

    |

  12. If sin theta = 3//5, find the values of costheta and tantheta.

    Text Solution

    |

  13. An inclined plane rises 1 in 10. if the length of the inclined plane i...

    Text Solution

    |

  14. Simplify the following : (i) (0.0036)^(1//5) (ii) (0.056)^(2//3) (ii...

    Text Solution

    |

  15. Simplify the following : (i) (0.05246)^(1//8) - 2.6055 (ii) (3.142xx...

    Text Solution

    |

  16. Find antilog of (i) - 2.6674 (ii) - 3.01 (iii) -0.3467

    Text Solution

    |

  17. Differentiate the following w.r.t.x (i) pi^2 (ii) e^2 (iii) -14

    Text Solution

    |

  18. Differentiate the following w.r.t.x (1) (3x +5) (ii) x^(-2) (iii) x^...

    Text Solution

    |

  19. Differentiate the following w.r.t.x (i) 3 x^(5//2) (ii) (4x)^(1//3) ...

    Text Solution

    |

  20. Differentiate the following w.r.tx (i) (5x^(2) +6)(2 x^(3) +4 ) (ii...

    Text Solution

    |