A particle starts from rest and its angular displacement (in red) is given by `theta = (t^2)/(20) +(t)/(5),` calculate the angular velocity at the end of t =4 second.

Answer

` 0.6 rad//s`

Explanation

Angular velocity `omega = (d theta)/(dt) = (d)/(dt)((t^2)/(20) + (t)/(5)) = (2t)/(20)+(1)/(5)` when t =4 s, `omega = (2xx4)/(20) +(1)/(5) = 0.6 rad//s`