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Find the value of x in the relation Y ...

Find the value of x in the relation
`Y = (T^x . Cos theta. Tau)/(L^3), where`
Y is Young's modulu. T is time period, `tau` is torque and L is length.

Text Solution

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`Y = (T^x cos theta tau)/(L^3)`
`T^x = (YL^3)/(cos theta, tau) = ([ML^(-1) T^(-2)][L^3])/([ML^2T^(-2)]) = 1 :. X = 0`
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