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Show that is e is electronic charge, h i...

Show that is e is electronic charge, h is Planck's constant, c is velocity of light and `in_0` is electirc permittivity of free space, then `e^2`/(4`pi``epsilon_0` hc) is dimensionless.

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To show that the expression \(\frac{e^2}{4\pi \epsilon_0 hc}\) is dimensionless, we will analyze the dimensions of each component in the expression. ### Step 1: Identify the dimensions of each component 1. **Electronic Charge (\(e\))**: The dimension of electric charge is given by the formula: \[ [e] = [I][T] = A \cdot s \] ...
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