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Calculate the angle between20 N force an...

Calculate the angle between`20 N` force and a `30 N` force so thea ther resultant is `40 N`.

Text Solution

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Here, ` A =20 N, B=30 N, `
`R=40 N , theta =?`
As, `R= sqrt(A^(2) + B^(2) + 2 AB cos theta)`
:. Cos theta =(R^(2) -A^(2) -B^(2))/(2 A B)`
`=((40)^(2) -(20)^(2) -(30^(2))/(2xx 20 xx 30) =(300)/(2 xx 20 xx 30)`
`= 0. 25 =cos 75 ^(@) 31'` gtbrgt :. theta =75 ^(@) 31'` .
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