A force is inclened at `60 ^(@)` to the horizontal . If its horizontal coponent in the horizonal direction is `60N` find themagitude of theforce and its vertical componet.

Explanation

Let (F) be the force applied, `theta =60^(00`.
Horizontal component of force, `F_(x) =F cos theta`
:. 60 =F cos 60^(0) =F xx 1//2`
or `F=60 xx 2 =120 N`
Verical component of force, `F sin theta =120 sin `60^(0)`
`=120 xx sqrt 3 // 2`
`=103 .92 N` .