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The direction of the oblique projectile ...

The direction of the oblique projectile becomes horizontal at the maximum height. What is the cause of it ?

Text Solution

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At the maximum height of projectile, of proectile, the vertical component velocity becomes zero and only horizontal component velocity of projectile is there.
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Knowledge Check

  • In a projectile motion, velocity at maximum height is

    A
    `(u cos theta)/(2)`
    B
    `u cos theta`
    C
    `(u sin theta)/(2)`
    D
    None of these

  • A body is thrown up with a speed u , at an angle of projection theta If the speed of the projectile becomes u/sqrt2 on reaching the maximum height , then the maximum vertical height attained by the projectile is

    A
    `(u^2)/(4g)`
    B
    `(u^2)/(3g)`
    C
    `u^2/(2g)`
    D
    `(u^2)/g`

  • If the time of flight of a projectile is doubled, what happens to the maximum height at tained?

    A
    halved
    B
    remains unchanged
    C
    doubled
    D
    become four times

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    The horizontal range of a projectile is R and the maximum height at tained by it is H. A strong windnow begins to blow in the direction of the motion of the projectile, giving it a constant horizontal acceleration = g/2. Under the same conditions of projection, the horizontal range of the projectile will now be:

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