A projectile is fired with kinetic energy ` 1 k J. If the range is maximum , what is its ` K.E. at the highest point ?

Explanation

Hecne, ` 1/2/ mv ^(2) = 1 k J =1000 J.
For maximum range, ` theta=45^(@)` and velocity of projectile at the hiest pint ` =v cos 45^(@)`.
At the highest point, ` KE =1/2 m ( v cos 45(@)^(@)`
`= 1/2 m v^(@)/2 =(1000)/2 = 500 J`.