A ball is released from the top of a tower of height h metre. It takes T second to reach the ground. What is the position of the ball in `T/3` second?

Explanation

Taking vertically downward motion fo ball from top fo tower to ground, we have
` u=0, a=g, S=h, t=T`
As ` S=ut + 1/2 at^(2)`
:. ` h=0 + 1/2 g T^(2) or T=sqrt (2 h)/g`
Distance coverd in time (T//3) s
` h' =1/2 g (T//3) ^(2) = h/9`
Height of the ball from gromund after ` T//3` seconds
` =h - h//9 =8 h//9`.