Define trajectory of a projectile and hence derive equation of motion of the projectile when projected at an angle ` theta` with horizontal direction.

For a projectile first with velocity u at an angle theta with the horizontal.

Find the equation of trajectory, time of flight , maximum height and horizontal range of a projectile when projected at an angle theta with the vertical direction .

Trajectory Of Horizontal Projectile

A particle is projected from the top of a tower of height h with a speed u at an angle theta above the horizontal . T_(1) =Time taken by the projectile to reach the height of tower again . T_(2) =Time taken by the projectile to move at right angle to initial direction of motion . V_(1) =Speed of the projectile when it moves at an angle theta//2 with the horizontal . V_(2) =Speed with projectile strikes the ground . .

For a projectile projected at an angle _____the maximum height and horizontal range are equal.

The question given below consist of an assertion and the reason . Use the following key to choose appropriate answer: Assertion: Range of projectile motion is same when particle is projected at an angle theta with the horizontal or at an angle (90^(@) -theta) with the horizontal . Reason : Range of projectile motion depended only on the angle of projection.

A projectile is projected with velocity u making angle theta with horizontal direction, find : time of flight.

A projectile is projected with velocity u making angle theta with horizontal direction, find : horizontal range.

The ratio of the speed of a projectile at the point of projection to the speed at the top of its trajectory is x. The angle of projection with the horizontal is

Find (a) time of flight , (b) Max.height (c ) Horizontal range of projectile projected with speed (v) making an angle theta with the horizontal direction from ground.