Home
Class 11
PHYSICS
Find (a) time of flight , (b) Max.height...

Find (a) time of flight , (b) Max.height (c ) Horizontal range of projectile projected with speed (v) making an angle ` theta` with the horizontal direction from ground.

Text Solution

AI Generated Solution

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • KINEMATICS

    PRADEEP|Exercise 5 Long answer (NCERT)|4 Videos

  • KINEMATICS

    PRADEEP|Exercise 6 Long answer (NCERT)|9 Videos

  • KINEMATICS

    PRADEEP|Exercise 3 Long answer|6 Videos

  • GRAVIATION

    PRADEEP|Exercise Assertion-Reason Type Questions|19 Videos

  • LAWS OF MOTION

    PRADEEP|Exercise Assertion- Reason Type Questions|17 Videos

Similar Questions

Explore conceptually related problems

A projectile is projected with velocity u making angle theta with horizontal direction, find : horizontal range.

A projectile is projected with velocity u making angle theta with horizontal direction, find : time of flight.

Knowledge Check

  • Particle A is projected with speed u at an angle theta with the horizontal . Another particle B is also projected with same speed u at an angle 90-theta with the horizontal . Both the projectiles are fired from the ground and reaches the ground after completing the projectile . Time of flight for A is t_(A) and that for B it is t_(B) . Range of the projectile A is R_(A) and that for B is R_(B) . Maximum height reached by the projectile A is h_(A) and that for B is h_(B)

    A
    `{:(P,Q,R,S),(2,3,4,1):}`
    B
    `{:(P,Q,R,S),(1,2,3,4):}`
    C
    `{:(P,Q,R,S),(2,4,1,3):}`
    D
    `{:(P,Q,R,S),(4,2,3,1):}`

  • The horizontal range of a projectile is times of its maximum height. Its angle of projection will be :-

    A
    `45^(@)`
    B
    `60^(@)`
    C
    `90^(@)`
    D
    `30^(@)`

    • Similar Questions

    Explore conceptually related problems

    Whe a projectile is projeected with velcity (v0 making an angle theta with the horizontal direction, then maximum horizontal range is…………………………… .

    Find the equation of trajectory, time of flight , maximum height and horizontal range of a projectile when projected at an angle theta with the vertical direction .

    At a height of 45 m from ground velocity of a projectile is, v = (30hati + 40hatj) m//s Find initial velocity, time of flight, maximum height and horizontal range of this projectile. Here hati and hatj are the unit vectors in horizontal and vertical directions.

    For a projectile projected at an angle _____the maximum height and horizontal range are equal.

    Prove that the time of flight T and the horizontal range R of a projectile are connected by the equation: gT^2 =2 R tan theta , where theta is the angle of projection.

    Statement-1 : A man projects a stone with speed u at some angle. He again projects a stone with same speed such that time of flight now is different. The horizontal ranges in both the cases may be same. (Neglect air friction) Statement-2 : The horizontal range is same for two projectiles projected with same speed if one is projected at an angle q with the horizontal and other is projected at an angle (90^(@) theta) with the horizontal. (Neglect air friction)

    Home
    Profile