Find (i) the time of flight (ii) maximum height and (iii) horizontal of a projectile given angular projection on an inclined plane where angle of inclination with horizontal is `theta_0`.

Find the equation of trajectory, time of flight , maximum height and horizontal range of a projectile when projected at an angle theta with the vertical direction .

A body is thrown at an angle alpha to the horizontal with initial velocity v_0 .Assuming air drag to be negligible , find (i)the time of motion, (ii)maximum height of ascent and the horizontal range, (iii)the angle of projection at which they are equal , (iv)the angle of projection at which the horizontal range is maximum and the angle at which the vertical range is maximum.

The velocity of a sphere rolling down an inclined plane of height h at an inclination theta with the horizontal, will be :

Find (a) time of flight , (b) Max.height (c ) Horizontal range of projectile projected with speed (v) making an angle theta with the horizontal direction from ground.

The horizontal range is four times the maximum height attained by a projectile. The angle of projection is

The horizontal range of a projectile is 2 sqrt(3) times its maximum height. Find the angle of projection.

During a projectile motion if the maximum height equal the horizontal range, then the angle of projection with the horizontal is :

If R and H represent horizontal range and maximum height of the projectile, then the angle of projection with the horizontal is