Two masses ` A and B` are moving in the same straight (A) moves with a uniform vlocity 11 ms^(-1)`. (B) starts from rest at the instant it is ` 52.5 m` ahead of (A) , and moves with a uniform acceleation ` 1 ms^(-2)`. When will ` A catch B`? Explain the double answer....

Explanation

To solve the problem, we need to determine when mass A, which moves with a constant velocity, will catch up to mass B, which starts from rest and accelerates uniformly.

### Step-by-Step Solution:

1. **Identify the Given Data:**
- Velocity of A, \( v_A = 11 \, \text{m/s} \)
- Initial position of B relative to A, \( d = 52.5 \, \text{m} \)
- Initial velocity of B, \( v_{B0} = 0 \, \text{m/s} \)
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