A jet airplance travelling at the speed of ` 500 km ^(-1)` ejects its products of combustion at the speed of ` 1500 km h^(-1)` relative to the jet plane. What is the speed of the later with respect to observer on the ground ?

Explanation

To solve the problem of finding the speed of the combustion products with respect to an observer on the ground, we can follow these steps:

### Step 1: Understand the given information
- The speed of the jet airplane with respect to the ground is \( v_{jet} = 500 \, \text{km/h} \).
- The speed of the products of combustion with respect to the jet airplane is \( v_{burn, jet} = 1500 \, \text{km/h} \).

### Step 2: Identify the direction of the speeds
- The jet is moving upwards (we can consider this as positive).
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