A cyclist starts from the centre O of a circular park of radius 1km, reaches the edge P of the park, then cycles along the PQ cicumference and returns to the centre along OQ as shown in fig. If the round trip taken ten minute, the net displacement and average speed of the cylists (in kilometer and kinetic per hour) is

Explanation

(a) Here, net displacement= zero.
(b0 Average velocity ` = (net displacement)/( time taken ) = 0/(10 // 60 h ) =0`
(c ) Average speed = ( total path length )/( time taken) = ( 1 km + ( 2 pi r)/4) + 1 km )/( (10// 60) h) = ( 12 + 2 xx (22) /7 ) xx 1/4 + 1)/( 1//6) = 21.4 km h^(-1)`.