A passenger arriving in a new town wishes to go from the station to a hotel located ` 10 km` away on a straight road from the station. A dishownest cabman takes him along a circuitons path ` 23 km` long and reaches the hotel in ` 28 minmtes` . What is (a) the average speed of the taxi, (b) the magnitude of average velocity ? Are the two equal ?

Explanation

Here, actual path length travelled, ` S= 23 km , Displacement= 10 km , Time taken , ` t= 28 min = 28 // 60 h`
(a) Average speed of the taxi ` (actual path length)/(tune taken ) = ( 23)/( 28 // 60 ) = 21 .4 km //h`
The aveage speed is bot equal to the magnitude of aveage veloctiy. The two ar equal fromthe motion of taxis along a straight parh in one direction.