An air craft executes a horizontal loop of radius ` 1 km` with s steady speed of ` 900 km h^(-1)`. Compare its centripetal acceleration with the acceleration due to gravity.

Explanation

Here, ` r= 1 km = 1000 m, v= 900 km h^(-1) =900 xx (1000 m) xx ( 60 xx 60 s)^(-1) = 250 ms^(-1)`
Centripetal acceleration, ` A= ( v^2 / r = (( 250)^2 /( 1000)`
Now , ` a/g = ((250 )^2)/(1000) xx 1/( 9.8) = 6. 38` .