Home
Class 11
PHYSICS
A particle starts from the origin at t=...

A particle starts from the origin at ` t=0` with a velocity of ` 10.0 hat j m//s` and moves in the X-y` plane with a constant accleration of ` ( 8.0 hat I + 2. 0 hat j ) ms^(-2) . (a) At wht time is the s-coordinate of the particle ` 16 m` ? What is the y-coordinate of the particle at that time ? ( b) What is the speed of the particle at that time ?

Text Solution

AI Generated Solution

To solve the problem step by step, we will break it down into parts (a) and (b) as given in the question. ### Given Data: - Initial position: \( \vec{r_0} = 0 \hat{i} + 0 \hat{j} \) (origin) - Initial velocity: \( \vec{u} = 0 \hat{i} + 10 \hat{j} \, \text{m/s} \) - Acceleration: \( \vec{a} = 8 \hat{i} + 2 \hat{j} \, \text{m/s}^2 \) ### Part (a): Finding the time when the x-coordinate is 16 m and the corresponding y-coordinate. ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • KINEMATICS

    PRADEEP|Exercise Higher order thinking skills|14 Videos

  • KINEMATICS

    PRADEEP|Exercise Value based|5 Videos

  • KINEMATICS

    PRADEEP|Exercise Additional Exercises|13 Videos

  • GRAVIATION

    PRADEEP|Exercise Assertion-Reason Type Questions|19 Videos

  • LAWS OF MOTION

    PRADEEP|Exercise Assertion- Reason Type Questions|17 Videos

Similar Questions

Explore conceptually related problems

A particle starts from the origin at t= 0 with a velocity of 8.0 hat j m//s and moves in the x-y plane with a constant acceleration of (4.0 hat i + 2.0 hat j) m//s^2. At the instant the particle's x-coordinate is 29 m, what are (a) its y-coordinate and (b) its speed ?

A paarticle starts from origin at t=0 with a vction 5.0 hat I m//s and moves in x-y plane under action of a force which produces a constant acceleration of ( 3.0 hat I + 2.0 ht j) m//s^(2) . (a) What is the y-cordinate of the particle at the instant its x-coordinate id 84 m ? (b) What is the speed of the particle at this time?

Knowledge Check

  • A particle starts from the origin at t=Os with a velocity of 10.0 hatj m//s and moves in the xy -plane with a constant acceleration of (8hati+2hatj)m//s^(-2) . What time is the x -coordinate of the particle 16m ?

    A
    `t=2s`
    B
    `t=4s`
    C
    `t=3s`
    D
    `t=1s`

  • A particle starts from the origin at t= 0 s with a velocity of 10.0 hatj m//s and moves in the xy -plane with a constant acceleration of (8hati+2hatj)m//s^(-2) . Then y -coordinate of the particle in 2 sec is

    A
    `24 m`
    B
    `16 m`
    C
    `8 m`
    D
    `12 m`

  • Starting from origin at t=0, with initial velocity 5 hat(j) m//s , a particle moves in the x-y plane with a constant acceleration of (10 hat(i) - 5hat(j))m//s^(2) . Find the coordinates of the particle at the moment its y-coordinate is maximum.

    A
    (5m, 5m)
    B
    (2.5m, 2.5m)
    C
    (5m, 2.5m)
    D
    (2.5m, 5m)

    • Similar Questions

    Explore conceptually related problems

    A particle starts from origin at t = 0 with a velocity 5.0hati m//s and moves in x-y plane under action of a force which produces a constant acceleration of (3.0hati+2.0hati)m//s^(2) : (a) What is the y-coordinate of the particle at the instant if its x-coordinate is 84m? (b) What is the speed of the particle this time?

    Starting from the origin at time t=0 ,with initial velocity [5hat jms^(-1) ,a particle moves in the x -y plane with a constant acceleration of ( 10ˆi+4ˆj)m/s 2 ms^(-2).At time t ,its coordinates are (20m,y_(0)m are,respectively:

    From the origin, a particle starts at t = 0 s with a velocity vecv=7.0hatim//s and moves in the xy plane with a constant acceleration of veca=(-9.0hati+3.0hatj)m//s^(2) . At the time the particle reaches the maximum x coordinate, what is its (a) velocity and (b) position vector?

    Starting from the origin at time t = 0 , with initial velocity 5hatj "ms"^(-1) , a particle moves in the x - y plane with a constant acceleration of (10hati+4hatj)ms^(-2) . At time t , its coordinates are (20 m,y_0 m) . The value of t and y_0 are , respectively :

    A particle leaves the origin with initial velocity vec(v)_(0)=11hat(i)+14 hat(j) m//s . It undergoes a constant acceleration given by vec(a)=-22/5 hat(i)+2/15 hat(j) m//s^(2) . When does the particle cross the y-axis ?

    Home
    Profile