A rectangular box is sliduing on a smooth inclined plane of inclination ` alpha, At `t=0` the box starts to move on the inclined plane . (A) bolt starts to fall from point (A) .Fig. 2 (HT). 2. Find the time after uhich bolt strikes the bottom surface of the box.

Explanation

As the block starts falling on the inclined plance, let at an instant, when the bolt reaches at (E ), its velocity be (v) parallel to (PQ). It then falls down due to gravity pull.
taking vetical downward moton perpendicular to plane (PQ) of the bolt, we have
.
` u=0, a=g cos alpha, S=l, t=?` ltBrgt As ` S= ut = 1/2 g cos alpha t^2 ` or t= sqrt (21)/( s cos alpha0`.